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115121303530151 = 417173275955787
BaseRepresentation
bin11010001011001111000100…
…011001110010101010100111
3120002121111012120122201020012
4122023033010121302222213
5110042121412200431101
61044501555144000435
733151145135336612
oct3213170431625247
9502544176581205
10115121303530151
1133754741700316
1210ab334376011b
134c30b7a6227a9
14205dc87bcd179
15d49881575bbb
hex68b3c4672aa7

115121303530151 has 4 divisors (see below), whose sum is σ = 115121579903112. Its totient is φ = 115121027157192.

The previous prime is 115121303530133. The next prime is 115121303530153. The reversal of 115121303530151 is 151035303121511.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-115121303530151 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (115121303530153) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 137560721 + ... + 138395066.

It is an arithmetic number, because the mean of its divisors is an integer number (28780394975778).

Almost surely, 2115121303530151 is an apocalyptic number.

115121303530151 is a deficient number, since it is larger than the sum of its proper divisors (276372961).

115121303530151 is an equidigital number, since it uses as much as digits as its factorization.

115121303530151 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 276372960.

The product of its (nonzero) digits is 6750, while the sum is 32.

Adding to 115121303530151 its reverse (151035303121511), we get a palindrome (266156606651662).

The spelling of 115121303530151 in words is "one hundred fifteen trillion, one hundred twenty-one billion, three hundred three million, five hundred thirty thousand, one hundred fifty-one".

Divisors: 1 417173 275955787 115121303530151