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115121322253 = 716445903179
BaseRepresentation
bin110101100110111000…
…0111111100100001101
3102000011000002002210001
41223031300333210031
53341232024303003
6124515213244301
711213546044060
oct1531560774415
9360130062701
10115121322253
1144905a92343
121a389a93691
13ab185264c2
1458014268d7
152edba1661d
hex1acdc3f90d

115121322253 has 4 divisors (see below), whose sum is σ = 131567225440. Its totient is φ = 98675419068.

The previous prime is 115121322247. The next prime is 115121322257. The reversal of 115121322253 is 352223121511.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-115121322253 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (115121322257) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8222951583 + ... + 8222951596.

It is an arithmetic number, because the mean of its divisors is an integer number (32891806360).

Almost surely, 2115121322253 is an apocalyptic number.

It is an amenable number.

115121322253 is a deficient number, since it is larger than the sum of its proper divisors (16445903187).

115121322253 is an equidigital number, since it uses as much as digits as its factorization.

115121322253 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 16445903186.

The product of its digits is 3600, while the sum is 28.

Adding to 115121322253 its reverse (352223121511), we get a palindrome (467344443764).

The spelling of 115121322253 in words is "one hundred fifteen billion, one hundred twenty-one million, three hundred twenty-two thousand, two hundred fifty-three".

Divisors: 1 7 16445903179 115121322253