Base | Representation |
---|---|
bin | 11010001011001111110100… |
… | …101011101111100000011011 |
3 | 120002121120022000211120211101 |
4 | 122023033310223233200123 |
5 | 110042130042031322141 |
6 | 1044502211401212231 |
7 | 33151204202332651 |
oct | 3213176453574033 |
9 | 502546260746741 |
10 | 115122113542171 |
11 | 3375501795a33a |
12 | 10ab352aa91077 |
13 | 4c30c7939c848 |
14 | 205dd23602dd1 |
15 | d498cc729531 |
hex | 68b3f4aef81b |
115122113542171 has 2 divisors, whose sum is σ = 115122113542172. Its totient is φ = 115122113542170.
The previous prime is 115122113542169. The next prime is 115122113542213. The reversal of 115122113542171 is 171245311221511.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 115122113542171 - 21 = 115122113542169 is a prime.
Together with 115122113542169, it forms a pair of twin primes.
It is a self number, because there is not a number n which added to its sum of digits gives 115122113542171.
It is not a weakly prime, because it can be changed into another prime (115122113549171) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57561056771085 + 57561056771086.
It is an arithmetic number, because the mean of its divisors is an integer number (57561056771086).
Almost surely, 2115122113542171 is an apocalyptic number.
115122113542171 is a deficient number, since it is larger than the sum of its proper divisors (1).
115122113542171 is an equidigital number, since it uses as much as digits as its factorization.
115122113542171 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 16800, while the sum is 37.
Adding to 115122113542171 its reverse (171245311221511), we get a palindrome (286367424763682).
The spelling of 115122113542171 in words is "one hundred fifteen trillion, one hundred twenty-two billion, one hundred thirteen million, five hundred forty-two thousand, one hundred seventy-one".
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