Base | Representation |
---|---|
bin | 10101011100010111… |
… | …11101010111111111 |
3 | 1002201022102200210021 |
4 | 22232023331113333 |
5 | 142034122231101 |
6 | 5142204353011 |
7 | 555166656604 |
oct | 125613752777 |
9 | 32638380707 |
10 | 11512305151 |
11 | 497843a286 |
12 | 2293545767 |
13 | 11160ca5a9 |
14 | 7b2d4a6ab |
15 | 475a385a1 |
hex | 2ae2fd5ff |
11512305151 has 2 divisors, whose sum is σ = 11512305152. Its totient is φ = 11512305150.
The previous prime is 11512305113. The next prime is 11512305163. The reversal of 11512305151 is 15150321511.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11512305151 - 227 = 11378087423 is a prime.
It is a super-2 number, since 2×115123051512 (a number of 21 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11512305551) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5756152575 + 5756152576.
It is an arithmetic number, because the mean of its divisors is an integer number (5756152576).
Almost surely, 211512305151 is an apocalyptic number.
11512305151 is a deficient number, since it is larger than the sum of its proper divisors (1).
11512305151 is an equidigital number, since it uses as much as digits as its factorization.
11512305151 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 750, while the sum is 25.
Adding to 11512305151 its reverse (15150321511), we get a palindrome (26662626662).
The spelling of 11512305151 in words is "eleven billion, five hundred twelve million, three hundred five thousand, one hundred fifty-one".
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