11512413016471 has 2 divisors, whose sum is σ = 11512413016472. Its totient is φ = 11512413016470.

The previous prime is 11512413016421. The next prime is 11512413016477. The reversal of 11512413016471 is 17461031421511.

11512413016471 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 11512413016471 - 2¹¹ = 11512413014423 is a prime.

It is a super-3 number, since 3×11512413016471³ (a number of 40 digits) contains 333 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 11512413016471.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11512413016477) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5756206508235 + 5756206508236.

It is an arithmetic number, because the mean of its divisors is an integer number (5756206508236).

Almost surely, 2^{11512413016471} is an apocalyptic number.

11512413016471 is a deficient number, since it is larger than the sum of its proper divisors (1).

11512413016471 is an equidigital number, since it uses as much as digits as its factorization.

11512413016471 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 20160, while the sum is 37.

Adding to 11512413016471 its reverse (17461031421511), we get a palindrome (28973444437982).

The spelling of 11512413016471 in words is "eleven trillion, five hundred twelve billion, four hundred thirteen million, sixteen thousand, four hundred seventy-one".