Base | Representation |
---|---|
bin | 1010011110000111011100… |
… | …1100100001100110001011 |
3 | 1111202120210202122012202221 |
4 | 2213201313030201212023 |
5 | 3002110111101002243 |
6 | 40252435225034511 |
7 | 2265515532314326 |
oct | 247416714414613 |
9 | 44676722565687 |
10 | 11512512125323 |
11 | 3739479a67350 |
12 | 135b251025a37 |
13 | 656818845781 |
14 | 2bb2cc4077bd |
15 | 14e7009bdbed |
hex | a787732198b |
11512512125323 has 4 divisors (see below), whose sum is σ = 12559104136728. Its totient is φ = 10465920113920.
The previous prime is 11512512125321. The next prime is 11512512125329. The reversal of 11512512125323 is 32352121521511.
11512512125323 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 11512512125323 - 21 = 11512512125321 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (11512512125321) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 523296005686 + ... + 523296005707.
It is an arithmetic number, because the mean of its divisors is an integer number (3139776034182).
Almost surely, 211512512125323 is an apocalyptic number.
11512512125323 is a deficient number, since it is larger than the sum of its proper divisors (1046592011405).
11512512125323 is a wasteful number, since it uses less digits than its factorization.
11512512125323 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1046592011404.
The product of its digits is 18000, while the sum is 34.
Adding to 11512512125323 its reverse (32352121521511), we get a palindrome (43864633646834).
The spelling of 11512512125323 in words is "eleven trillion, five hundred twelve billion, five hundred twelve million, one hundred twenty-five thousand, three hundred twenty-three".
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