115125433 has 4 divisors (see below), whose sum is σ = 115831888. Its totient is φ = 114418980.

The previous prime is 115125403. The next prime is 115125457. The reversal of 115125433 is 334521511.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 334521511 = 433 ⋅772567.

It is a cyclic number.

It is not a de Polignac number, because 115125433 - 2⁹ = 115124921 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 115125398 and 115125407.

It is not an unprimeable number, because it can be changed into a prime (115125403) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 352983 + ... + 353308.

It is an arithmetic number, because the mean of its divisors is an integer number (28957972).

Almost surely, 2^115125433 is an apocalyptic number.

It is an amenable number.

115125433 is a deficient number, since it is larger than the sum of its proper divisors (706455).

115125433 is an equidigital number, since it uses as much as digits as its factorization.

115125433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 706454.

The product of its digits is 1800, while the sum is 25.

The square root of 115125433 is about 10729.6520446844. The cubic root of 115125433 is about 486.4711528297.

Adding to 115125433 its reverse (334521511), we get a palindrome (449646944).

The spelling of 115125433 in words is "one hundred fifteen million, one hundred twenty-five thousand, four hundred thirty-three".