Base | Representation |
---|---|
bin | 100010010011111… |
… | …0111000111001100 |
3 | 2222020101002202101 |
4 | 1010213313013030 |
5 | 4324213100134 |
6 | 310124204444 |
7 | 40346613616 |
oct | 10447670714 |
9 | 2866332671 |
10 | 1151300044 |
11 | 540973844 |
12 | 281699724 |
13 | 1546a2a3b |
14 | acc93db6 |
15 | 6b11ae14 |
hex | 449f71cc |
1151300044 has 12 divisors (see below), whose sum is σ = 2133291384. Its totient is φ = 541788224.
The previous prime is 1151300039. The next prime is 1151300053. The reversal of 1151300044 is 4400031511.
It is a junction number, because it is equal to n+sod(n) for n = 1151299994 and 1151300030.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8465374 + ... + 8465509.
It is an arithmetic number, because the mean of its divisors is an integer number (177774282).
Almost surely, 21151300044 is an apocalyptic number.
It is an amenable number.
1151300044 is a deficient number, since it is larger than the sum of its proper divisors (981991340).
1151300044 is a wasteful number, since it uses less digits than its factorization.
1151300044 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 16930904 (or 16930902 counting only the distinct ones).
The product of its (nonzero) digits is 240, while the sum is 19.
The square root of 1151300044 is about 33930.8126044750. The cubic root of 1151300044 is about 1048.0841994293.
Adding to 1151300044 its reverse (4400031511), we get a palindrome (5551331555).
The spelling of 1151300044 in words is "one billion, one hundred fifty-one million, three hundred thousand, forty-four".
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