Base | Representation |
---|---|
bin | 1010011110001001010101… |
… | …1110000010000001101111 |
3 | 1111202122010011100111111112 |
4 | 2213202111132002001233 |
5 | 3002112131111443322 |
6 | 40253001451142235 |
7 | 2265534240406211 |
oct | 247422536020157 |
9 | 44678104314445 |
10 | 11513020031087 |
11 | 373970a733483 |
12 | 135b37314497b |
13 | 656899b38123 |
14 | 2bb339a5a5b1 |
15 | 14e7303995e2 |
hex | a789578206f |
11513020031087 has 2 divisors, whose sum is σ = 11513020031088. Its totient is φ = 11513020031086.
The previous prime is 11513020031081. The next prime is 11513020031143. The reversal of 11513020031087 is 78013002031511.
It is a weak prime.
It is an emirp because it is prime and its reverse (78013002031511) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11513020031087 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11513020031081) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5756510015543 + 5756510015544.
It is an arithmetic number, because the mean of its divisors is an integer number (5756510015544).
Almost surely, 211513020031087 is an apocalyptic number.
11513020031087 is a deficient number, since it is larger than the sum of its proper divisors (1).
11513020031087 is an equidigital number, since it uses as much as digits as its factorization.
11513020031087 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 5040, while the sum is 32.
Adding to 11513020031087 its reverse (78013002031511), we get a palindrome (89526022062598).
The spelling of 11513020031087 in words is "eleven trillion, five hundred thirteen billion, twenty million, thirty-one thousand, eighty-seven".
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