Base | Representation |
---|---|
bin | 10000110000001111100… |
… | …011100010100001100001 |
3 | 11002001201221001010002121 |
4 | 100300033203202201201 |
5 | 122330341411210032 |
6 | 2240523332144241 |
7 | 146115406213324 |
oct | 20601743424141 |
9 | 4061657033077 |
10 | 1151312210017 |
11 | 4042a5800932 |
12 | 167170168081 |
13 | 84750669718 |
14 | 3da1c1b67bb |
15 | 1ee35648a97 |
hex | 10c0f8e2861 |
1151312210017 has 2 divisors, whose sum is σ = 1151312210018. Its totient is φ = 1151312210016.
The previous prime is 1151312210003. The next prime is 1151312210021. The reversal of 1151312210017 is 7100122131511.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 739352340736 + 411959869281 = 859856^2 + 641841^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1151312210017 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1151312209973 and 1151312210000.
It is not a weakly prime, because it can be changed into another prime (1151312210047) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 575656105008 + 575656105009.
It is an arithmetic number, because the mean of its divisors is an integer number (575656105009).
Almost surely, 21151312210017 is an apocalyptic number.
It is an amenable number.
1151312210017 is a deficient number, since it is larger than the sum of its proper divisors (1).
1151312210017 is an equidigital number, since it uses as much as digits as its factorization.
1151312210017 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 420, while the sum is 25.
Adding to 1151312210017 its reverse (7100122131511), we get a palindrome (8251434341528).
The spelling of 1151312210017 in words is "one trillion, one hundred fifty-one billion, three hundred twelve million, two hundred ten thousand, seventeen".
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