Base | Representation |
---|---|
bin | 11010001011011000011010… |
… | …010101011100101011101111 |
3 | 120002122110002200221122112201 |
4 | 122023120122111130223233 |
5 | 110042302433300313303 |
6 | 1044510334420442331 |
7 | 33151651546004452 |
oct | 3213303225345357 |
9 | 502573080848481 |
10 | 115131335166703 |
11 | 33758a1a263339 |
12 | 10ab52832493a7 |
13 | 4c31ab8a38acb |
14 | 206055a229499 |
15 | d49c6c0d281d |
hex | 68b61a55caef |
115131335166703 has 2 divisors, whose sum is σ = 115131335166704. Its totient is φ = 115131335166702.
The previous prime is 115131335166667. The next prime is 115131335166719. The reversal of 115131335166703 is 307661533131511.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-115131335166703 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (115131335166403) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57565667583351 + 57565667583352.
It is an arithmetic number, because the mean of its divisors is an integer number (57565667583352).
Almost surely, 2115131335166703 is an apocalyptic number.
115131335166703 is a deficient number, since it is larger than the sum of its proper divisors (1).
115131335166703 is an equidigital number, since it uses as much as digits as its factorization.
115131335166703 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 510300, while the sum is 46.
The spelling of 115131335166703 in words is "one hundred fifteen trillion, one hundred thirty-one billion, three hundred thirty-five million, one hundred sixty-six thousand, seven hundred three".
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