Base | Representation |
---|---|
bin | 11010001011011000100101… |
… | …000001101101111000101111 |
3 | 120002122110120012110221110211 |
4 | 122023120211001231320233 |
5 | 110042303320210344123 |
6 | 1044510404305243251 |
7 | 33151656154456402 |
oct | 3213304501557057 |
9 | 502573505427424 |
10 | 115131514543663 |
11 | 3375900153a962 |
12 | 10ab5313333527 |
13 | 4c31b16c52217 |
14 | 2060575d9dd39 |
15 | d49c7cc1640d |
hex | 68b62506de2f |
115131514543663 has 2 divisors, whose sum is σ = 115131514543664. Its totient is φ = 115131514543662.
The previous prime is 115131514543607. The next prime is 115131514543729. The reversal of 115131514543663 is 366345415131511.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-115131514543663 is a prime.
It is a super-2 number, since 2×1151315145436632 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (115131514543603) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57565757271831 + 57565757271832.
It is an arithmetic number, because the mean of its divisors is an integer number (57565757271832).
Almost surely, 2115131514543663 is an apocalyptic number.
115131514543663 is a deficient number, since it is larger than the sum of its proper divisors (1).
115131514543663 is an equidigital number, since it uses as much as digits as its factorization.
115131514543663 is an evil number, because the sum of its binary digits is even.
The product of its digits is 1944000, while the sum is 49.
The spelling of 115131514543663 in words is "one hundred fifteen trillion, one hundred thirty-one billion, five hundred fourteen million, five hundred forty-three thousand, six hundred sixty-three".
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