115132143500401 has 4 divisors (see below), whose sum is σ = 115146220063600. Its totient is φ = 115118066937204.

The previous prime is 115132143500357. The next prime is 115132143500411. The reversal of 115132143500401 is 104005341231511.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 115132143500401 - 2⁹ = 115132143499889 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (115132143500411) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7038269331 + ... + 7038285688.

It is an arithmetic number, because the mean of its divisors is an integer number (28786555015900).

Almost surely, 2^{115132143500401} is an apocalyptic number.

It is an amenable number.

115132143500401 is a deficient number, since it is larger than the sum of its proper divisors (14076563199).

115132143500401 is an equidigital number, since it uses as much as digits as its factorization.

115132143500401 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 14076563198.

The product of its (nonzero) digits is 7200, while the sum is 31.

Adding to 115132143500401 its reverse (104005341231511), we get a palindrome (219137484731912).

The spelling of 115132143500401 in words is "one hundred fifteen trillion, one hundred thirty-two billion, one hundred forty-three million, five hundred thousand, four hundred one".