Base | Representation |
---|---|
bin | 11010001011011001001010… |
… | …100011000010101000110111 |
3 | 120002122112012001222111011220 |
4 | 122023121022203002220313 |
5 | 110042311112333131112 |
6 | 1044510550553401423 |
7 | 33152010600202251 |
oct | 3213311243025067 |
9 | 502575161874156 |
10 | 115132144036407 |
11 | 337592a49020a3 |
12 | 10ab546a109273 |
13 | 4c31bb74a5c34 |
14 | 20605d5822cd1 |
15 | d49cb810c98c |
hex | 68b64a8c2a37 |
115132144036407 has 8 divisors (see below), whose sum is σ = 156775685496576. Its totient is φ = 75121682633592.
The previous prime is 115132144036373. The next prime is 115132144036487. The reversal of 115132144036407 is 704630441231511.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 115132144036407 - 222 = 115132139842103 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (115132144036487) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 408270014173 + ... + 408270014454.
It is an arithmetic number, because the mean of its divisors is an integer number (19596960687072).
Almost surely, 2115132144036407 is an apocalyptic number.
115132144036407 is a deficient number, since it is larger than the sum of its proper divisors (41643541460169).
115132144036407 is an equidigital number, since it uses as much as digits as its factorization.
115132144036407 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 816540028677.
The product of its (nonzero) digits is 241920, while the sum is 42.
Adding to 115132144036407 its reverse (704630441231511), we get a palindrome (819762585267918).
The spelling of 115132144036407 in words is "one hundred fifteen trillion, one hundred thirty-two billion, one hundred forty-four million, thirty-six thousand, four hundred seven".
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