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115132165207555 = 5143471604965013
BaseRepresentation
bin11010001011011001001011…
…110011110011011000000011
3120002122112020112211002112111
4122023121023303303120003
5110042311133243120210
61044510553031240151
733152011245146566
oct3213311363633003
9502575215732474
10115132165207555
1133759305852311
1210ab5475219057
134c31bbb9a9442
1420605d85744dd
15d49cb9de088a
hex68b64bcf3603

115132165207555 has 8 divisors (see below), whose sum is σ = 138168228125232. Its totient is φ = 92099312248608.

The previous prime is 115132165207537. The next prime is 115132165207567. The reversal of 115132165207555 is 555702561231511.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 115132165207555 - 27 = 115132165207427 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 115132165207499 and 115132165207508.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 802410772 + ... + 802554241.

It is an arithmetic number, because the mean of its divisors is an integer number (17271028515654).

Almost surely, 2115132165207555 is an apocalyptic number.

115132165207555 is a deficient number, since it is larger than the sum of its proper divisors (23036062917677).

115132165207555 is a wasteful number, since it uses less digits than its factorization.

115132165207555 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1604979365.

The product of its (nonzero) digits is 1575000, while the sum is 49.

The spelling of 115132165207555 in words is "one hundred fifteen trillion, one hundred thirty-two billion, one hundred sixty-five million, two hundred seven thousand, five hundred fifty-five".

Divisors: 1 5 14347 71735 1604965013 8024825065 23026433041511 115132165207555