Base | Representation |
---|---|
bin | 11010001011011001001011… |
… | …110011110011011000000011 |
3 | 120002122112020112211002112111 |
4 | 122023121023303303120003 |
5 | 110042311133243120210 |
6 | 1044510553031240151 |
7 | 33152011245146566 |
oct | 3213311363633003 |
9 | 502575215732474 |
10 | 115132165207555 |
11 | 33759305852311 |
12 | 10ab5475219057 |
13 | 4c31bbb9a9442 |
14 | 20605d85744dd |
15 | d49cb9de088a |
hex | 68b64bcf3603 |
115132165207555 has 8 divisors (see below), whose sum is σ = 138168228125232. Its totient is φ = 92099312248608.
The previous prime is 115132165207537. The next prime is 115132165207567. The reversal of 115132165207555 is 555702561231511.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 115132165207555 - 27 = 115132165207427 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 115132165207499 and 115132165207508.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 802410772 + ... + 802554241.
It is an arithmetic number, because the mean of its divisors is an integer number (17271028515654).
Almost surely, 2115132165207555 is an apocalyptic number.
115132165207555 is a deficient number, since it is larger than the sum of its proper divisors (23036062917677).
115132165207555 is a wasteful number, since it uses less digits than its factorization.
115132165207555 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1604979365.
The product of its (nonzero) digits is 1575000, while the sum is 49.
The spelling of 115132165207555 in words is "one hundred fifteen trillion, one hundred thirty-two billion, one hundred sixty-five million, two hundred seven thousand, five hundred fifty-five".
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