Base | Representation |
---|---|
bin | 11010001011011001100010… |
… | …001011001101011011011010 |
3 | 120002122120012200212222212202 |
4 | 122023121202023031123122 |
5 | 110042312420323123310 |
6 | 1044511054154010202 |
7 | 33152023452454535 |
oct | 3213314213153332 |
9 | 502576180788782 |
10 | 115132540442330 |
11 | 337594886427a4 |
12 | 10ab555aa16962 |
13 | 4c31c4b659658 |
14 | 206063232da1c |
15 | d49cdcd113a5 |
hex | 68b6622cd6da |
115132540442330 has 8 divisors (see below), whose sum is σ = 207238572796212. Its totient is φ = 46053016176928.
The previous prime is 115132540442327. The next prime is 115132540442351. The reversal of 115132540442330 is 33244045231511.
It can be written as a sum of positive squares in 2 ways, for example, as 107247502345369 + 7885038096961 = 10356037^2 + 2808031^2 .
It is a sphenic number, since it is the product of 3 distinct primes.
It is a Curzon number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5756627022107 + ... + 5756627022126.
Almost surely, 2115132540442330 is an apocalyptic number.
115132540442330 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
115132540442330 is a deficient number, since it is larger than the sum of its proper divisors (92106032353882).
115132540442330 is a wasteful number, since it uses less digits than its factorization.
115132540442330 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 11513254044240.
The product of its (nonzero) digits is 172800, while the sum is 38.
Adding to 115132540442330 its reverse (33244045231511), we get a palindrome (148376585673841).
The spelling of 115132540442330 in words is "one hundred fifteen trillion, one hundred thirty-two billion, five hundred forty million, four hundred forty-two thousand, three hundred thirty".
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