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115132540442330 = 2511513254044233
BaseRepresentation
bin11010001011011001100010…
…001011001101011011011010
3120002122120012200212222212202
4122023121202023031123122
5110042312420323123310
61044511054154010202
733152023452454535
oct3213314213153332
9502576180788782
10115132540442330
11337594886427a4
1210ab555aa16962
134c31c4b659658
14206063232da1c
15d49cdcd113a5
hex68b6622cd6da

115132540442330 has 8 divisors (see below), whose sum is σ = 207238572796212. Its totient is φ = 46053016176928.

The previous prime is 115132540442327. The next prime is 115132540442351. The reversal of 115132540442330 is 33244045231511.

It can be written as a sum of positive squares in 2 ways, for example, as 107247502345369 + 7885038096961 = 10356037^2 + 2808031^2 .

It is a sphenic number, since it is the product of 3 distinct primes.

It is a Curzon number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5756627022107 + ... + 5756627022126.

Almost surely, 2115132540442330 is an apocalyptic number.

115132540442330 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

115132540442330 is a deficient number, since it is larger than the sum of its proper divisors (92106032353882).

115132540442330 is a wasteful number, since it uses less digits than its factorization.

115132540442330 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 11513254044240.

The product of its (nonzero) digits is 172800, while the sum is 38.

Adding to 115132540442330 its reverse (33244045231511), we get a palindrome (148376585673841).

The spelling of 115132540442330 in words is "one hundred fifteen trillion, one hundred thirty-two billion, five hundred forty million, four hundred forty-two thousand, three hundred thirty".

Divisors: 1 2 5 10 11513254044233 23026508088466 57566270221165 115132540442330