Base | Representation |
---|---|
bin | 1010011110001010100011… |
… | …0100010001100101101111 |
3 | 1111202122221210010210021021 |
4 | 2213202220310101211233 |
5 | 3002113312211112403 |
6 | 40253054004315011 |
7 | 2265545261425132 |
oct | 247425064214557 |
9 | 44678853123237 |
10 | 11513344629103 |
11 | 37398669887a9 |
12 | 135b4439a2a67 |
13 | 65691c169165 |
14 | 2bb36abd4219 |
15 | 14e74db168bd |
hex | a78a8d1196f |
11513344629103 has 2 divisors, whose sum is σ = 11513344629104. Its totient is φ = 11513344629102.
The previous prime is 11513344629053. The next prime is 11513344629113. The reversal of 11513344629103 is 30192644331511.
11513344629103 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11513344629103 - 217 = 11513344498031 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 11513344629103.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11513344629113) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5756672314551 + 5756672314552.
It is an arithmetic number, because the mean of its divisors is an integer number (5756672314552).
Almost surely, 211513344629103 is an apocalyptic number.
11513344629103 is a deficient number, since it is larger than the sum of its proper divisors (1).
11513344629103 is an equidigital number, since it uses as much as digits as its factorization.
11513344629103 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 233280, while the sum is 43.
The spelling of 11513344629103 in words is "eleven trillion, five hundred thirteen billion, three hundred forty-four million, six hundred twenty-nine thousand, one hundred three".
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