11513445025241 has 16 divisors (see below), whose sum is σ = 12433976576784. Its totient is φ = 10620379920384.

The previous prime is 11513445025231. The next prime is 11513445025267. The reversal of 11513445025241 is 14252054431511.

It can be written as a sum of positive squares in 8 ways, for example, as 491071585225 + 11022373440016 = 700765^2 + 3319996^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-11513445025241 is a prime.

It is a super-2 number, since 2×11513445025241² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11513445025195 and 11513445025204.

It is not an unprimeable number, because it can be changed into a prime (11513445025231) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 5974610 + ... + 7663083.

It is an arithmetic number, because the mean of its divisors is an integer number (777123536049).

Almost surely, 2^{11513445025241} is an apocalyptic number.

It is an amenable number.

11513445025241 is a deficient number, since it is larger than the sum of its proper divisors (920531551543).

11513445025241 is a wasteful number, since it uses less digits than its factorization.

11513445025241 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 13638700.

The product of its (nonzero) digits is 96000, while the sum is 38.

Adding to 11513445025241 its reverse (14252054431511), we get a palindrome (25765499456752).

The spelling of 11513445025241 in words is "eleven trillion, five hundred thirteen billion, four hundred forty-five million, twenty-five thousand, two hundred forty-one".