1151350433 has 2 divisors, whose sum is σ = 1151350434. Its totient is φ = 1151350432.

The previous prime is 1151350411. The next prime is 1151350451. The reversal of 1151350433 is 3340531511.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 982947904 + 168402529 = 31352^2 + 12977^2 .

It is a cyclic number.

It is not a de Polignac number, because 1151350433 - 2¹⁴ = 1151334049 is a prime.

It is not a weakly prime, because it can be changed into another prime (1151350463) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 575675216 + 575675217.

It is an arithmetic number, because the mean of its divisors is an integer number (575675217).

Almost surely, 2^1151350433 is an apocalyptic number.

It is an amenable number.

1151350433 is a deficient number, since it is larger than the sum of its proper divisors (1).

1151350433 is an equidigital number, since it uses as much as digits as its factorization.

1151350433 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2700, while the sum is 26.

The square root of 1151350433 is about 33931.5551220394. Note that the first 3 decimals coincide. The cubic root of 1151350433 is about 1048.0994897221.

Adding to 1151350433 its reverse (3340531511), we get a palindrome (4491881944).

The spelling of 1151350433 in words is "one billion, one hundred fifty-one million, three hundred fifty thousand, four hundred thirty-three".