Base | Representation |
---|---|
bin | 110101100111100000… |
… | …1110010111001100101 |
3 | 102000012110221020201120 |
4 | 1223033001302321211 |
5 | 3341302440112122 |
6 | 124521251244153 |
7 | 11214224064411 |
oct | 1531701627145 |
9 | 360173836646 |
10 | 115142504037 |
11 | 44916a3a550 |
12 | 1a394ba9659 |
13 | ab1ca317c2 |
14 | 580417bd41 |
15 | 2edd7ec75c |
hex | 1acf072e65 |
115142504037 has 32 divisors (see below), whose sum is σ = 171953058816. Its totient is φ = 67927267200.
The previous prime is 115142503997. The next prime is 115142504051. The reversal of 115142504037 is 730405241511.
It is not a de Polignac number, because 115142504037 - 211 = 115142501989 is a prime.
It is a super-2 number, since 2×1151425040372 (a number of 23 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (33).
It is a junction number, because it is equal to n+sod(n) for n = 115142503989 and 115142504007.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (115142504437) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 503328 + ... + 695430.
It is an arithmetic number, because the mean of its divisors is an integer number (5373533088).
Almost surely, 2115142504037 is an apocalyptic number.
It is an amenable number.
115142504037 is a deficient number, since it is larger than the sum of its proper divisors (56810554779).
115142504037 is a wasteful number, since it uses less digits than its factorization.
115142504037 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 192601.
The product of its (nonzero) digits is 16800, while the sum is 33.
Adding to 115142504037 its reverse (730405241511), we get a palindrome (845547745548).
The spelling of 115142504037 in words is "one hundred fifteen billion, one hundred forty-two million, five hundred four thousand, thirty-seven".
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