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115143224513 is a prime number
BaseRepresentation
bin110101100111100010…
…0100010110011000001
3102000012112021212000212
41223033010202303001
53341303131141023
6124521314523505
711214233155052
oct1531704426301
9360175255025
10115143224513
1144917391889
121a395296595
13ab1cc24715
1458042c8729
152edd8e0e78
hex1acf122cc1

115143224513 has 2 divisors, whose sum is σ = 115143224514. Its totient is φ = 115143224512.

The previous prime is 115143224491. The next prime is 115143224681. The reversal of 115143224513 is 315422341511.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 65542144144 + 49601080369 = 256012^2 + 222713^2 .

It is a cyclic number.

It is not a de Polignac number, because 115143224513 - 212 = 115143220417 is a prime.

It is a super-2 number, since 2×1151432245132 (a number of 23 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 115143224513.

It is not a weakly prime, because it can be changed into another prime (115143224113) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57571612256 + 57571612257.

It is an arithmetic number, because the mean of its divisors is an integer number (57571612257).

Almost surely, 2115143224513 is an apocalyptic number.

It is an amenable number.

115143224513 is a deficient number, since it is larger than the sum of its proper divisors (1).

115143224513 is an equidigital number, since it uses as much as digits as its factorization.

115143224513 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 14400, while the sum is 32.

The spelling of 115143224513 in words is "one hundred fifteen billion, one hundred forty-three million, two hundred twenty-four thousand, five hundred thirteen".