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115152443114441 is a prime number
BaseRepresentation
bin11010001011101100000100…
…011101111000001111001001
3120002201110120202021111100212
4122023230010131320033021
5110043124200414130231
61044524145125210505
733153326613415625
oct3213540435701711
9502643522244325
10115152443114441
1133766971135947
1210ab9394260a35
134c33aa0b17b05
14206159d71c185
15d4a5a525442b
hex68bb047783c9

115152443114441 has 2 divisors, whose sum is σ = 115152443114442. Its totient is φ = 115152443114440.

The previous prime is 115152443114419. The next prime is 115152443114503. The reversal of 115152443114441 is 144411344251511.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 100383947834041 + 14768495280400 = 10019179^2 + 3842980^2 .

It is a cyclic number.

It is not a de Polignac number, because 115152443114441 - 238 = 114877565207497 is a prime.

It is not a weakly prime, because it can be changed into another prime (115152443114411) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57576221557220 + 57576221557221.

It is an arithmetic number, because the mean of its divisors is an integer number (57576221557221).

Almost surely, 2115152443114441 is an apocalyptic number.

It is an amenable number.

115152443114441 is a deficient number, since it is larger than the sum of its proper divisors (1).

115152443114441 is an equidigital number, since it uses as much as digits as its factorization.

115152443114441 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 153600, while the sum is 41.

Adding to 115152443114441 its reverse (144411344251511), we get a palindrome (259563787365952).

The spelling of 115152443114441 in words is "one hundred fifteen trillion, one hundred fifty-two billion, four hundred forty-three million, one hundred fourteen thousand, four hundred forty-one".