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115152522324113 is a prime number
BaseRepresentation
bin11010001011101100001001…
…001100000010100010010001
3120002201110210021022202121102
4122023230021030002202101
5110043124331203332423
61044524201035034145
733153331564610621
oct3213541114024221
9502643707282542
10115152522324113
1133766a0191728a
1210ab93b689b955
134c33ab435c541
1420615aa05a881
15d4a5ac19dc28
hex68bb09302891

115152522324113 has 2 divisors, whose sum is σ = 115152522324114. Its totient is φ = 115152522324112.

The previous prime is 115152522324029. The next prime is 115152522324121. The reversal of 115152522324113 is 311423225251511.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 114687114568849 + 465407755264 = 10709207^2 + 682208^2 .

It is a cyclic number.

It is not a de Polignac number, because 115152522324113 - 28 = 115152522323857 is a prime.

It is not a weakly prime, because it can be changed into another prime (115152522324173) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57576261162056 + 57576261162057.

It is an arithmetic number, because the mean of its divisors is an integer number (57576261162057).

Almost surely, 2115152522324113 is an apocalyptic number.

It is an amenable number.

115152522324113 is a deficient number, since it is larger than the sum of its proper divisors (1).

115152522324113 is an equidigital number, since it uses as much as digits as its factorization.

115152522324113 is an evil number, because the sum of its binary digits is even.

The product of its digits is 72000, while the sum is 38.

Adding to 115152522324113 its reverse (311423225251511), we get a palindrome (426575747575624).

The spelling of 115152522324113 in words is "one hundred fifteen trillion, one hundred fifty-two billion, five hundred twenty-two million, three hundred twenty-four thousand, one hundred thirteen".