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115152553525117 is a prime number
BaseRepresentation
bin11010001011101100001011…
…000011000011111101111101
3120002201110212110000221100011
4122023230023003003331331
5110043124412200300432
61044524204111503221
733153332424040633
oct3213541303037575
9502643773027304
10115152553525117
1133766a18498039
1210ab9405227b11
134c33aba965084
1420615b025d353
15d4a5aecb3847
hex68bb0b0c3f7d

115152553525117 has 2 divisors, whose sum is σ = 115152553525118. Its totient is φ = 115152553525116.

The previous prime is 115152553524991. The next prime is 115152553525211. The reversal of 115152553525117 is 711525355251511.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 100501005950361 + 14651547574756 = 10025019^2 + 3827734^2 .

It is a cyclic number.

It is not a de Polignac number, because 115152553525117 - 219 = 115152553000829 is a prime.

It is a super-2 number, since 2×1151525535251172 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (115152553225117) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57576276762558 + 57576276762559.

It is an arithmetic number, because the mean of its divisors is an integer number (57576276762559).

Almost surely, 2115152553525117 is an apocalyptic number.

It is an amenable number.

115152553525117 is a deficient number, since it is larger than the sum of its proper divisors (1).

115152553525117 is an equidigital number, since it uses as much as digits as its factorization.

115152553525117 is an evil number, because the sum of its binary digits is even.

The product of its digits is 1312500, while the sum is 49.

The spelling of 115152553525117 in words is "one hundred fifteen trillion, one hundred fifty-two billion, five hundred fifty-three million, five hundred twenty-five thousand, one hundred seventeen".