Base | Representation |
---|---|
bin | 110101100111110101… |
… | …0010000111111001011 |
3 | 102000020012220020112102 |
4 | 1223033222100333023 |
5 | 3341313144104120 |
6 | 124522310504015 |
7 | 11214413211422 |
oct | 1531752207713 |
9 | 360205806472 |
10 | 115153113035 |
11 | 44921a26214 |
12 | 1a39866500b |
13 | ab21ca760c |
14 | 58057402b9 |
15 | 2ede6e5d75 |
hex | 1acfa90fcb |
115153113035 has 8 divisors (see below), whose sum is σ = 138203634240. Its totient is φ = 92109224704.
The previous prime is 115153113017. The next prime is 115153113041. The reversal of 115153113035 is 530311351511.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 115153113035 - 28 = 115153112779 is a prime.
It is a super-2 number, since 2×1151531130352 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 115153112989 and 115153113007.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1619942 + ... + 1689531.
It is an arithmetic number, because the mean of its divisors is an integer number (17275454280).
Almost surely, 2115153113035 is an apocalyptic number.
115153113035 is a deficient number, since it is larger than the sum of its proper divisors (23050521205).
115153113035 is an equidigital number, since it uses as much as digits as its factorization.
115153113035 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3316437.
The product of its (nonzero) digits is 3375, while the sum is 29.
Adding to 115153113035 its reverse (530311351511), we get a palindrome (645464464546).
The spelling of 115153113035 in words is "one hundred fifteen billion, one hundred fifty-three million, one hundred thirteen thousand, thirty-five".
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