Base | Representation |
---|---|
bin | 10101011101010010… |
… | …10100000110100101 |
3 | 1002201211220122201021 |
4 | 22232221110012211 |
5 | 142043110003141 |
6 | 5143041331141 |
7 | 555322250026 |
oct | 125651240645 |
9 | 32654818637 |
10 | 11520000421 |
11 | 4981815906 |
12 | 2296036ab1 |
13 | 11178930c7 |
14 | 7b3d90c4d |
15 | 4765586d1 |
hex | 2aea541a5 |
11520000421 has 2 divisors, whose sum is σ = 11520000422. Its totient is φ = 11520000420.
The previous prime is 11520000403. The next prime is 11520000451. The reversal of 11520000421 is 12400002511.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 11430603396 + 89397025 = 106914^2 + 9455^2 .
It is a cyclic number.
It is not a de Polignac number, because 11520000421 - 25 = 11520000389 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 11520000395 and 11520000404.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11520000451) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5760000210 + 5760000211.
It is an arithmetic number, because the mean of its divisors is an integer number (5760000211).
Almost surely, 211520000421 is an apocalyptic number.
It is an amenable number.
11520000421 is a deficient number, since it is larger than the sum of its proper divisors (1).
11520000421 is an equidigital number, since it uses as much as digits as its factorization.
11520000421 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 80, while the sum is 16.
Adding to 11520000421 its reverse (12400002511), we get a palindrome (23920002932).
The spelling of 11520000421 in words is "eleven billion, five hundred twenty million, four hundred twenty-one", and thus it is an aban number.
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