1152004642141 has 2 divisors, whose sum is σ = 1152004642142. Its totient is φ = 1152004642140.

The previous prime is 1152004642121. The next prime is 1152004642171. The reversal of 1152004642141 is 1412464002511.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 869649502500 + 282355139641 = 932550^2 + 531371^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1152004642141 is a prime.

It is a super-3 number, since 3×1152004642141³ (a number of 37 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1152004642121) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 576002321070 + 576002321071.

It is an arithmetic number, because the mean of its divisors is an integer number (576002321071).

Almost surely, 2^{1152004642141} is an apocalyptic number.

It is an amenable number.

1152004642141 is a deficient number, since it is larger than the sum of its proper divisors (1).

1152004642141 is an equidigital number, since it uses as much as digits as its factorization.

1152004642141 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 7680, while the sum is 31.

Adding to 1152004642141 its reverse (1412464002511), we get a palindrome (2564468644652).

The spelling of 1152004642141 in words is "one trillion, one hundred fifty-two billion, four million, six hundred forty-two thousand, one hundred forty-one".