Base | Representation |
---|---|
bin | 1010011110100011110010… |
… | …1010100001001100100101 |
3 | 1111210022102222022200120011 |
4 | 2213220330222201030211 |
5 | 3002221201214114403 |
6 | 40300134201410221 |
7 | 2266205212620016 |
oct | 247507452411445 |
9 | 44708388280504 |
10 | 11520120066853 |
11 | 37417234a3432 |
12 | 1360814a99971 |
13 | 65745ba97c18 |
14 | 2bb8109b700d |
15 | 14e9e8873a6d |
hex | a7a3caa1325 |
11520120066853 has 2 divisors, whose sum is σ = 11520120066854. Its totient is φ = 11520120066852.
The previous prime is 11520120066761. The next prime is 11520120066869. The reversal of 11520120066853 is 35866002102511.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 9310785644164 + 2209334422689 = 3051358^2 + 1486383^2 .
It is a cyclic number.
It is not a de Polignac number, because 11520120066853 - 217 = 11520119935781 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11520120066883) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5760060033426 + 5760060033427.
It is an arithmetic number, because the mean of its divisors is an integer number (5760060033427).
Almost surely, 211520120066853 is an apocalyptic number.
It is an amenable number.
11520120066853 is a deficient number, since it is larger than the sum of its proper divisors (1).
11520120066853 is an equidigital number, since it uses as much as digits as its factorization.
11520120066853 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 86400, while the sum is 40.
The spelling of 11520120066853 in words is "eleven trillion, five hundred twenty billion, one hundred twenty million, sixty-six thousand, eight hundred fifty-three".
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