Base | Representation |
---|---|
bin | 10101011101010011… |
… | …11000101100101110 |
3 | 1002201212012021100000 |
4 | 22232221320230232 |
5 | 142043124302233 |
6 | 5143044445130 |
7 | 555323443035 |
oct | 125651705456 |
9 | 32655167300 |
10 | 11520150318 |
11 | 4981908496 |
12 | 22960a97a6 |
13 | 11179163c1 |
14 | 7b3dcd71c |
15 | 476587d13 |
hex | 2aea78b2e |
11520150318 has 48 divisors (see below), whose sum is σ = 26584412400. Its totient is φ = 3736259136.
The previous prime is 11520150311. The next prime is 11520150353. The reversal of 11520150318 is 81305102511.
11520150318 is a `hidden beast` number, since 1 + 152 + 0 + 1 + 503 + 1 + 8 = 666.
It is a super-2 number, since 2×115201503182 (a number of 21 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (27).
It is a junction number, because it is equal to n+sod(n) for n = 11520150291 and 11520150300.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11520150311) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 302343 + ... + 338306.
It is an arithmetic number, because the mean of its divisors is an integer number (553841925).
Almost surely, 211520150318 is an apocalyptic number.
11520150318 is a gapful number since it is divisible by the number (18) formed by its first and last digit.
11520150318 is an abundant number, since it is smaller than the sum of its proper divisors (15064262082).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
11520150318 is an equidigital number, since it uses as much as digits as its factorization.
11520150318 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 640703 (or 640691 counting only the distinct ones).
The product of its (nonzero) digits is 1200, while the sum is 27.
Adding to 11520150318 its reverse (81305102511), we get a palindrome (92825252829).
The spelling of 11520150318 in words is "eleven billion, five hundred twenty million, one hundred fifty thousand, three hundred eighteen".
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