Base | Representation |
---|---|
bin | 10101011101010100… |
… | …01100011011100101 |
3 | 1002201212100101012110 |
4 | 22232222030123211 |
5 | 142043134344031 |
6 | 5143050311233 |
7 | 555324230466 |
oct | 125652143345 |
9 | 32655311173 |
10 | 11520231141 |
11 | 4981963191 |
12 | 2296128519 |
13 | 1117944123 |
14 | 7b4010d6d |
15 | 4765a1c46 |
hex | 2aea8c6e5 |
11520231141 has 4 divisors (see below), whose sum is σ = 15360308192. Its totient is φ = 7680154092.
The previous prime is 11520231137. The next prime is 11520231143. The reversal of 11520231141 is 14113202511.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is not a de Polignac number, because 11520231141 - 22 = 11520231137 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11520231143) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1920038521 + ... + 1920038526.
It is an arithmetic number, because the mean of its divisors is an integer number (3840077048).
Almost surely, 211520231141 is an apocalyptic number.
It is an amenable number.
11520231141 is a deficient number, since it is larger than the sum of its proper divisors (3840077051).
11520231141 is an equidigital number, since it uses as much as digits as its factorization.
11520231141 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3840077050.
The product of its (nonzero) digits is 240, while the sum is 21.
Adding to 11520231141 its reverse (14113202511), we get a palindrome (25633433652).
The spelling of 11520231141 in words is "eleven billion, five hundred twenty million, two hundred thirty-one thousand, one hundred forty-one".
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