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11520311465693 is a prime number
BaseRepresentation
bin1010011110100100100000…
…0100101001011011011101
31111210022221022110202102002
42213221020010221123131
53002222044213400233
640300205200012045
72266213025522102
oct247511004513335
944708838422362
1011520311465693
113741811541198
121360869001025
1365748c630284
142bb82c19aaa9
1514ea0a57e6e8
hexa7a481296dd

11520311465693 has 2 divisors, whose sum is σ = 11520311465694. Its totient is φ = 11520311465692.

The previous prime is 11520311465603. The next prime is 11520311465701. The reversal of 11520311465693 is 39656411302511.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 6389782951204 + 5130528514489 = 2527802^2 + 2265067^2 .

It is a cyclic number.

It is not a de Polignac number, because 11520311465693 - 230 = 11519237723869 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11520311465603) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5760155732846 + 5760155732847.

It is an arithmetic number, because the mean of its divisors is an integer number (5760155732847).

Almost surely, 211520311465693 is an apocalyptic number.

It is an amenable number.

11520311465693 is a deficient number, since it is larger than the sum of its proper divisors (1).

11520311465693 is an equidigital number, since it uses as much as digits as its factorization.

11520311465693 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 583200, while the sum is 47.

The spelling of 11520311465693 in words is "eleven trillion, five hundred twenty billion, three hundred eleven million, four hundred sixty-five thousand, six hundred ninety-three".