11520321414137 has 2 divisors, whose sum is σ = 11520321414138. Its totient is φ = 11520321414136.

The previous prime is 11520321414101. The next prime is 11520321414143. The reversal of 11520321414137 is 73141412302511.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 8943233794576 + 2577087619561 = 2990524^2 + 1605331^2 .

It is a cyclic number.

It is not a de Polignac number, because 11520321414137 - 2²² = 11520317219833 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 11520321414097 and 11520321414106.

It is not a weakly prime, because it can be changed into another prime (11520321414157) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5760160707068 + 5760160707069.

It is an arithmetic number, because the mean of its divisors is an integer number (5760160707069).

Almost surely, 2^{11520321414137} is an apocalyptic number.

It is an amenable number.

11520321414137 is a deficient number, since it is larger than the sum of its proper divisors (1).

11520321414137 is an equidigital number, since it uses as much as digits as its factorization.

11520321414137 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 20160, while the sum is 35.

Adding to 11520321414137 its reverse (73141412302511), we get a palindrome (84661733716648).

The spelling of 11520321414137 in words is "eleven trillion, five hundred twenty billion, three hundred twenty-one million, four hundred fourteen thousand, one hundred thirty-seven".