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11520461121253 = 73453747652667
BaseRepresentation
bin1010011110100101000011…
…1111100010011011100101
31111210100022202002001020121
42213221100333202123211
53002222401021340003
640300232103401541
72266216523545510
oct247512077423345
944710282061217
1011520461121253
113741888a68677
1213608ab1532b1
136574b463b466
142bb843dd5d77
1514ea18791cbd
hexa7a50fe26e5

11520461121253 has 8 divisors (see below), whose sum is σ = 13166622779072. Its totient is φ = 9874394837856.

The previous prime is 11520461121203. The next prime is 11520461121259. The reversal of 11520461121253 is 35212116402511.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 11520461121253 - 213 = 11520461113061 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11520461121259) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 23584575 + ... + 24068092.

It is an arithmetic number, because the mean of its divisors is an integer number (1645827847384).

Almost surely, 211520461121253 is an apocalyptic number.

It is an amenable number.

11520461121253 is a deficient number, since it is larger than the sum of its proper divisors (1646161657819).

11520461121253 is an equidigital number, since it uses as much as digits as its factorization.

11520461121253 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 47687211.

The product of its (nonzero) digits is 14400, while the sum is 34.

Adding to 11520461121253 its reverse (35212116402511), we get a palindrome (46732577523764).

The spelling of 11520461121253 in words is "eleven trillion, five hundred twenty billion, four hundred sixty-one million, one hundred twenty-one thousand, two hundred fifty-three".

Divisors: 1 7 34537 241759 47652667 333568669 1645780160179 11520461121253