Base | Representation |
---|---|
bin | 1010011110100101001110… |
… | …0011100101011011101001 |
3 | 1111210100102201222212111221 |
4 | 2213221103203211123221 |
5 | 3002222443024001121 |
6 | 40300240241222041 |
7 | 2266220555224363 |
oct | 247512343453351 |
9 | 44710381885457 |
10 | 11520504125161 |
11 | 3741900270099 |
12 | 1360901631921 |
13 | 6574c0517365 |
14 | 2bb8499cbd33 |
15 | 14ea1c438b41 |
hex | a7a538e56e9 |
11520504125161 has 2 divisors, whose sum is σ = 11520504125162. Its totient is φ = 11520504125160.
The previous prime is 11520504125159. The next prime is 11520504125177. The reversal of 11520504125161 is 16152140502511.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 8619767171136 + 2900736954025 = 2935944^2 + 1703155^2 .
It is a cyclic number.
It is not a de Polignac number, because 11520504125161 - 21 = 11520504125159 is a prime.
Together with 11520504125159, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (11520504125461) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5760252062580 + 5760252062581.
It is an arithmetic number, because the mean of its divisors is an integer number (5760252062581).
Almost surely, 211520504125161 is an apocalyptic number.
It is an amenable number.
11520504125161 is a deficient number, since it is larger than the sum of its proper divisors (1).
11520504125161 is an equidigital number, since it uses as much as digits as its factorization.
11520504125161 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 12000, while the sum is 34.
Adding to 11520504125161 its reverse (16152140502511), we get a palindrome (27672644627672).
The spelling of 11520504125161 in words is "eleven trillion, five hundred twenty billion, five hundred four million, one hundred twenty-five thousand, one hundred sixty-one".
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