11520654343003 has 4 divisors (see below), whose sum is σ = 12406858523248. Its totient is φ = 10634450162760.

The previous prime is 11520654342983. The next prime is 11520654343031. The reversal of 11520654343003 is 30034345602511.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-11520654343003 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (11520654343603) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 443102090103 + ... + 443102090128.

It is an arithmetic number, because the mean of its divisors is an integer number (3101714630812).

Almost surely, 2^{11520654343003} is an apocalyptic number.

11520654343003 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

11520654343003 is a deficient number, since it is larger than the sum of its proper divisors (886204180245).

11520654343003 is an equidigital number, since it uses as much as digits as its factorization.

11520654343003 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 886204180244.

The product of its (nonzero) digits is 129600, while the sum is 37.

Adding to 11520654343003 its reverse (30034345602511), we get a palindrome (41554999945514).

The spelling of 11520654343003 in words is "eleven trillion, five hundred twenty billion, six hundred fifty-four million, three hundred forty-three thousand, three".