Base | Representation |
---|---|
bin | 11010001100100011000110… |
… | …101111101110110000010011 |
3 | 120002221010010010010111002112 |
4 | 122030203012233232300103 |
5 | 110100111212002231242 |
6 | 1045011241031335535 |
7 | 33160521202420541 |
oct | 3214430657566023 |
9 | 502833103114075 |
10 | 115211537148947 |
11 | 33789a36186698 |
12 | 10b089268215ab |
13 | 4c3952a970235 |
14 | 20643a7b40d91 |
15 | d4bdb319cc82 |
hex | 68c8c6beec13 |
115211537148947 has 2 divisors, whose sum is σ = 115211537148948. Its totient is φ = 115211537148946.
The previous prime is 115211537148899. The next prime is 115211537148949. The reversal of 115211537148947 is 749841735112511.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 115211537148947 - 238 = 114936659242003 is a prime.
Together with 115211537148949, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (115211537148949) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57605768574473 + 57605768574474.
It is an arithmetic number, because the mean of its divisors is an integer number (57605768574474).
Almost surely, 2115211537148947 is an apocalyptic number.
115211537148947 is a deficient number, since it is larger than the sum of its proper divisors (1).
115211537148947 is an equidigital number, since it uses as much as digits as its factorization.
115211537148947 is an evil number, because the sum of its binary digits is even.
The product of its digits is 8467200, while the sum is 59.
The spelling of 115211537148947 in words is "one hundred fifteen trillion, two hundred eleven billion, five hundred thirty-seven million, one hundred forty-eight thousand, nine hundred forty-seven".
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