Base | Representation |
---|---|
bin | 110101101001101001… |
… | …1110100001010000010 |
3 | 102000101111002201112102 |
4 | 1223103103310022002 |
5 | 3341424332233032 |
6 | 124532335030402 |
7 | 11216055463046 |
oct | 1532323641202 |
9 | 360344081472 |
10 | 115214336642 |
11 | 44953542439 |
12 | 1a3b506b402 |
13 | ab318924c2 |
14 | 580d91a026 |
15 | 2ee4c8b362 |
hex | 1ad34f4282 |
115214336642 has 4 divisors (see below), whose sum is σ = 172821504966. Its totient is φ = 57607168320.
The previous prime is 115214336641. The next prime is 115214336647. The reversal of 115214336642 is 246633412511.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 114574803121 + 639533521 = 338489^2 + 25289^2 .
It is a super-2 number, since 2×1152143366422 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 115214336596 and 115214336605.
It is not an unprimeable number, because it can be changed into a prime (115214336641) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 28803584159 + ... + 28803584162.
Almost surely, 2115214336642 is an apocalyptic number.
115214336642 is a deficient number, since it is larger than the sum of its proper divisors (57607168324).
115214336642 is an equidigital number, since it uses as much as digits as its factorization.
115214336642 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 57607168323.
The product of its digits is 103680, while the sum is 38.
The spelling of 115214336642 in words is "one hundred fifteen billion, two hundred fourteen million, three hundred thirty-six thousand, six hundred forty-two".
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