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1152152051 = 1667691153
BaseRepresentation
bin100010010101100…
…0111000111110011
32222021222101111012
41010223013013303
54324422331201
6310154341135
740360062611
oct10453070763
92867871435
101152152051
115413a5986
12281a2a7ab
1315491079b
14ad0366b1
156b2385bb
hex44ac71f3

1152152051 has 4 divisors (see below), whose sum is σ = 1152844872. Its totient is φ = 1151459232.

The previous prime is 1152152047. The next prime is 1152152063. The reversal of 1152152051 is 1502512511.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 1502512511 = 10714042173.

It is a cyclic number.

It is not a de Polignac number, because 1152152051 - 22 = 1152152047 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1152152021) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 343910 + ... + 347243.

It is an arithmetic number, because the mean of its divisors is an integer number (288211218).

Almost surely, 21152152051 is an apocalyptic number.

1152152051 is a deficient number, since it is larger than the sum of its proper divisors (692821).

1152152051 is an equidigital number, since it uses as much as digits as its factorization.

1152152051 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 692820.

The product of its (nonzero) digits is 500, while the sum is 23.

The square root of 1152152051 is about 33943.3653458227. The cubic root of 1152152051 is about 1048.3426767598.

Adding to 1152152051 its reverse (1502512511), we get a palindrome (2654664562).

The spelling of 1152152051 in words is "one billion, one hundred fifty-two million, one hundred fifty-two thousand, fifty-one".

Divisors: 1 1667 691153 1152152051