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11522045173 is a prime number
BaseRepresentation
bin10101011101100010…
…00111010011110101
31002201222202112120211
422232301013103311
5142044120421143
65143153225421
7555345524302
oct125661072365
932658675524
1011522045173
114982992091
122296862271
13111812aa12
147b43640a9
1547680e49d
hex2aec474f5

11522045173 has 2 divisors, whose sum is σ = 11522045174. Its totient is φ = 11522045172.

The previous prime is 11522045111. The next prime is 11522045209. The reversal of 11522045173 is 37154022511.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 11521231569 + 813604 = 107337^2 + 902^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-11522045173 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11522045473) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5761022586 + 5761022587.

It is an arithmetic number, because the mean of its divisors is an integer number (5761022587).

Almost surely, 211522045173 is an apocalyptic number.

It is an amenable number.

11522045173 is a deficient number, since it is larger than the sum of its proper divisors (1).

11522045173 is an equidigital number, since it uses as much as digits as its factorization.

11522045173 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 8400, while the sum is 31.

Adding to 11522045173 its reverse (37154022511), we get a palindrome (48676067684).

The spelling of 11522045173 in words is "eleven billion, five hundred twenty-two million, forty-five thousand, one hundred seventy-three".