Base | Representation |
---|---|
bin | 11010001100101111111011… |
… | …111100001011001001100001 |
3 | 120002222102200021122201000112 |
4 | 122030233323330023021201 |
5 | 110100322421003132223 |
6 | 1045021440112101105 |
7 | 33161516465132345 |
oct | 3214577374131141 |
9 | 502872607581015 |
10 | 115225314505313 |
11 | 33794866136421 |
12 | 10b0b530834795 |
13 | 4c3a9150c72cc |
14 | 2064d1381d625 |
15 | d4c41c9a2778 |
hex | 68cbfbf0b261 |
115225314505313 has 2 divisors, whose sum is σ = 115225314505314. Its totient is φ = 115225314505312.
The previous prime is 115225314505309. The next prime is 115225314505319. The reversal of 115225314505313 is 313505413522511.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 78699041077504 + 36526273427809 = 8871248^2 + 6043697^2 .
It is a cyclic number.
It is not a de Polignac number, because 115225314505313 - 22 = 115225314505309 is a prime.
It is not a weakly prime, because it can be changed into another prime (115225314505319) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57612657252656 + 57612657252657.
It is an arithmetic number, because the mean of its divisors is an integer number (57612657252657).
Almost surely, 2115225314505313 is an apocalyptic number.
It is an amenable number.
115225314505313 is a deficient number, since it is larger than the sum of its proper divisors (1).
115225314505313 is an equidigital number, since it uses as much as digits as its factorization.
115225314505313 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 270000, while the sum is 41.
The spelling of 115225314505313 in words is "one hundred fifteen trillion, two hundred twenty-five billion, three hundred fourteen million, five hundred five thousand, three hundred thirteen".
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