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115225314505313 is a prime number
BaseRepresentation
bin11010001100101111111011…
…111100001011001001100001
3120002222102200021122201000112
4122030233323330023021201
5110100322421003132223
61045021440112101105
733161516465132345
oct3214577374131141
9502872607581015
10115225314505313
1133794866136421
1210b0b530834795
134c3a9150c72cc
142064d1381d625
15d4c41c9a2778
hex68cbfbf0b261

115225314505313 has 2 divisors, whose sum is σ = 115225314505314. Its totient is φ = 115225314505312.

The previous prime is 115225314505309. The next prime is 115225314505319. The reversal of 115225314505313 is 313505413522511.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 78699041077504 + 36526273427809 = 8871248^2 + 6043697^2 .

It is a cyclic number.

It is not a de Polignac number, because 115225314505313 - 22 = 115225314505309 is a prime.

It is not a weakly prime, because it can be changed into another prime (115225314505319) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57612657252656 + 57612657252657.

It is an arithmetic number, because the mean of its divisors is an integer number (57612657252657).

Almost surely, 2115225314505313 is an apocalyptic number.

It is an amenable number.

115225314505313 is a deficient number, since it is larger than the sum of its proper divisors (1).

115225314505313 is an equidigital number, since it uses as much as digits as its factorization.

115225314505313 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 270000, while the sum is 41.

The spelling of 115225314505313 in words is "one hundred fifteen trillion, two hundred twenty-five billion, three hundred fourteen million, five hundred five thousand, three hundred thirteen".