Base | Representation |
---|---|
bin | 11010001100101111111011… |
… | …111100001011001001100111 |
3 | 120002222102200021122201000202 |
4 | 122030233323330023021213 |
5 | 110100322421003132234 |
6 | 1045021440112101115 |
7 | 33161516465132354 |
oct | 3214577374131147 |
9 | 502872607581022 |
10 | 115225314505319 |
11 | 33794866136427 |
12 | 10b0b53083479b |
13 | 4c3a9150c7305 |
14 | 2064d1381d62b |
15 | d4c41c9a277e |
hex | 68cbfbf0b267 |
115225314505319 has 2 divisors, whose sum is σ = 115225314505320. Its totient is φ = 115225314505318.
The previous prime is 115225314505313. The next prime is 115225314505393. The reversal of 115225314505319 is 913505413522511.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-115225314505319 is a prime.
It is a super-2 number, since 2×1152253145053192 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (115225314505313) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57612657252659 + 57612657252660.
It is an arithmetic number, because the mean of its divisors is an integer number (57612657252660).
Almost surely, 2115225314505319 is an apocalyptic number.
115225314505319 is a deficient number, since it is larger than the sum of its proper divisors (1).
115225314505319 is an equidigital number, since it uses as much as digits as its factorization.
115225314505319 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 810000, while the sum is 47.
The spelling of 115225314505319 in words is "one hundred fifteen trillion, two hundred twenty-five billion, three hundred fourteen million, five hundred five thousand, three hundred nineteen".
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