115230511204231 has 2 divisors, whose sum is σ = 115230511204232. Its totient is φ = 115230511204230.

The previous prime is 115230511204213. The next prime is 115230511204253. The reversal of 115230511204231 is 132402115032511.

Together with previous prime (115230511204213) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 115230511204231 - 2³³ = 115221921269639 is a prime.

It is a super-3 number, since 3×115230511204231³ (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a junction number, because it is equal to n+sod(n) for n = 115230511204193 and 115230511204202.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (115230511204271) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57615255602115 + 57615255602116.

It is an arithmetic number, because the mean of its divisors is an integer number (57615255602116).

Almost surely, 2^{115230511204231} is an apocalyptic number.

115230511204231 is a deficient number, since it is larger than the sum of its proper divisors (1).

115230511204231 is an equidigital number, since it uses as much as digits as its factorization.

115230511204231 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 7200, while the sum is 31.

Adding to 115230511204231 its reverse (132402115032511), we get a palindrome (247632626236742).

The spelling of 115230511204231 in words is "one hundred fifteen trillion, two hundred thirty billion, five hundred eleven million, two hundred four thousand, two hundred thirty-one".