Base | Representation |
---|---|
bin | 11010001100110101100011… |
… | …001111001011111110011011 |
3 | 120010000000020101102001212121 |
4 | 122030311203033023332123 |
5 | 110100422242140304404 |
6 | 1045024314205122111 |
7 | 33162122042256103 |
oct | 3214654317137633 |
9 | 503000211361777 |
10 | 115231342509979 |
11 | 33797379854563 |
12 | 10b10733559337 |
13 | 4c3b365c19a87 |
14 | 206532623c203 |
15 | d4c671cbce54 |
hex | 68cd633cbf9b |
115231342509979 has 2 divisors, whose sum is σ = 115231342509980. Its totient is φ = 115231342509978.
The previous prime is 115231342509971. The next prime is 115231342510007. The reversal of 115231342509979 is 979905243132511.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 115231342509979 - 23 = 115231342509971 is a prime.
It is not a weakly prime, because it can be changed into another prime (115231342509971) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57615671254989 + 57615671254990.
It is an arithmetic number, because the mean of its divisors is an integer number (57615671254990).
Almost surely, 2115231342509979 is an apocalyptic number.
115231342509979 is a deficient number, since it is larger than the sum of its proper divisors (1).
115231342509979 is an equidigital number, since it uses as much as digits as its factorization.
115231342509979 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 18370800, while the sum is 61.
The spelling of 115231342509979 in words is "one hundred fifteen trillion, two hundred thirty-one billion, three hundred forty-two million, five hundred nine thousand, nine hundred seventy-nine".
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