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115231342510007 is a prime number
BaseRepresentation
bin11010001100110101100011…
…001111001011111110110111
3120010000000020101102001220122
4122030311203033023332313
5110100422242140310012
61045024314205122155
733162122042256143
oct3214654317137667
9503000211361818
10115231342510007
1133797379854589
1210b1073355935b
134c3b365c19aa9
14206532623c223
15d4c671cbce72
hex68cd633cbfb7

115231342510007 has 2 divisors, whose sum is σ = 115231342510008. Its totient is φ = 115231342510006.

The previous prime is 115231342509979. The next prime is 115231342510027. The reversal of 115231342510007 is 700015243132511.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 115231342510007 - 218 = 115231342247863 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (115231342510027) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57615671255003 + 57615671255004.

It is an arithmetic number, because the mean of its divisors is an integer number (57615671255004).

Almost surely, 2115231342510007 is an apocalyptic number.

115231342510007 is a deficient number, since it is larger than the sum of its proper divisors (1).

115231342510007 is an equidigital number, since it uses as much as digits as its factorization.

115231342510007 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 25200, while the sum is 35.

Adding to 115231342510007 its reverse (700015243132511), we get a palindrome (815246585642518).

The spelling of 115231342510007 in words is "one hundred fifteen trillion, two hundred thirty-one billion, three hundred forty-two million, five hundred ten thousand, seven".