Base | Representation |
---|---|
bin | 11010001100110101100011… |
… | …001111001011111111001011 |
3 | 120010000000020101102001221101 |
4 | 122030311203033023333023 |
5 | 110100422242140310102 |
6 | 1045024314205122231 |
7 | 33162122042256202 |
oct | 3214654317137713 |
9 | 503000211361841 |
10 | 115231342510027 |
11 | 337973798545a7 |
12 | 10b10733559377 |
13 | 4c3b365c19ac3 |
14 | 206532623c239 |
15 | d4c671cbce87 |
hex | 68cd633cbfcb |
115231342510027 has 2 divisors, whose sum is σ = 115231342510028. Its totient is φ = 115231342510026.
The previous prime is 115231342510007. The next prime is 115231342510043. The reversal of 115231342510027 is 720015243132511.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 115231342510027 - 223 = 115231334121419 is a prime.
It is not a weakly prime, because it can be changed into another prime (115231342510007) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57615671255013 + 57615671255014.
It is an arithmetic number, because the mean of its divisors is an integer number (57615671255014).
Almost surely, 2115231342510027 is an apocalyptic number.
115231342510027 is a deficient number, since it is larger than the sum of its proper divisors (1).
115231342510027 is an equidigital number, since it uses as much as digits as its factorization.
115231342510027 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 50400, while the sum is 37.
Adding to 115231342510027 its reverse (720015243132511), we get a palindrome (835246585642538).
The spelling of 115231342510027 in words is "one hundred fifteen trillion, two hundred thirty-one billion, three hundred forty-two million, five hundred ten thousand, twenty-seven".
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