Base | Representation |
---|---|
bin | 11010001100110110100101… |
… | …010001110011110010101101 |
3 | 120010000010002121021110200111 |
4 | 122030312211101303302231 |
5 | 110100432024311243423 |
6 | 1045025020145100021 |
7 | 33162161355053065 |
oct | 3214664521636255 |
9 | 503003077243614 |
10 | 115232450493613 |
11 | 33797898222012 |
12 | 10b109a2627611 |
13 | 4c3b4b16345ab |
14 | 20653cd4583a5 |
15 | d4c6d91ce60d |
hex | 68cda5473cad |
115232450493613 has 2 divisors, whose sum is σ = 115232450493614. Its totient is φ = 115232450493612.
The previous prime is 115232450493599. The next prime is 115232450493653. The reversal of 115232450493613 is 316394054232511.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 63383205281449 + 51849245212164 = 7961357^2 + 7200642^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-115232450493613 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (115232450493653) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57616225246806 + 57616225246807.
It is an arithmetic number, because the mean of its divisors is an integer number (57616225246807).
Almost surely, 2115232450493613 is an apocalyptic number.
It is an amenable number.
115232450493613 is a deficient number, since it is larger than the sum of its proper divisors (1).
115232450493613 is an equidigital number, since it uses as much as digits as its factorization.
115232450493613 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2332800, while the sum is 49.
The spelling of 115232450493613 in words is "one hundred fifteen trillion, two hundred thirty-two billion, four hundred fifty million, four hundred ninety-three thousand, six hundred thirteen".
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