Base | Representation |
---|---|
bin | 1010011110101111110000… |
… | …1111100110011111101100 |
3 | 1111210121201222100101221002 |
4 | 2213223330033212133230 |
5 | 3002244242031024030 |
6 | 40301425140255432 |
7 | 2266350651612656 |
oct | 247537417463754 |
9 | 44717658311832 |
10 | 11523334236140 |
11 | 3743022844391 |
12 | 13613713a1578 |
13 | 657851957c3c |
14 | 2bba3780d6d6 |
15 | 14eb35b20245 |
hex | a7afc3e67ec |
11523334236140 has 12 divisors (see below), whose sum is σ = 24199001895936. Its totient is φ = 4609333694448.
The previous prime is 11523334236133. The next prime is 11523334236163. The reversal of 11523334236140 is 4163243332511.
It is a junction number, because it is equal to n+sod(n) for n = 11523334236094 and 11523334236103.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 288083355884 + ... + 288083355923.
It is an arithmetic number, because the mean of its divisors is an integer number (2016583491328).
Almost surely, 211523334236140 is an apocalyptic number.
11523334236140 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
11523334236140 is an abundant number, since it is smaller than the sum of its proper divisors (12675667659796).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
11523334236140 is a wasteful number, since it uses less digits than its factorization.
11523334236140 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 576166711816 (or 576166711814 counting only the distinct ones).
The product of its (nonzero) digits is 155520, while the sum is 38.
Adding to 11523334236140 its reverse (4163243332511), we get a palindrome (15686577568651).
The spelling of 11523334236140 in words is "eleven trillion, five hundred twenty-three billion, three hundred thirty-four million, two hundred thirty-six thousand, one hundred forty".
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