11523646011133 has 4 divisors (see below), whose sum is σ = 11718962045280. Its totient is φ = 11328329976988.

The previous prime is 11523646011113. The next prime is 11523646011193. The reversal of 11523646011133 is 33111064632511.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-11523646011133 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11523646011092 and 11523646011101.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11523646011113) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 97658016985 + ... + 97658017102.

It is an arithmetic number, because the mean of its divisors is an integer number (2929740511320).

Almost surely, 2^{11523646011133} is an apocalyptic number.

It is an amenable number.

11523646011133 is a deficient number, since it is larger than the sum of its proper divisors (195316034147).

11523646011133 is an equidigital number, since it uses as much as digits as its factorization.

11523646011133 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 195316034146.

The product of its (nonzero) digits is 38880, while the sum is 37.

The spelling of 11523646011133 in words is "eleven trillion, five hundred twenty-three billion, six hundred forty-six million, eleven thousand, one hundred thirty-three".