Base | Representation |
---|---|
bin | 11010001101000000101000… |
… | …100111110111011000001011 |
3 | 120010001010221211012200201101 |
4 | 122031000220213313120023 |
5 | 110101121130432302410 |
6 | 1045034003200002231 |
7 | 33163023006421465 |
oct | 3215005047673013 |
9 | 503033854180641 |
10 | 115243244025355 |
11 | 337a142695a186 |
12 | 10b12ab5300377 |
13 | 4c3c51184b774 |
14 | 2065b34b41135 |
15 | d4cb1ba87d3a |
hex | 68d0289f760b |
115243244025355 has 4 divisors (see below), whose sum is σ = 138291892830432. Its totient is φ = 92194595220280.
The previous prime is 115243244025353. The next prime is 115243244025461. The reversal of 115243244025355 is 553520442342511.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 115243244025355 - 21 = 115243244025353 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (115243244025353) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 11524324402531 + ... + 11524324402540.
It is an arithmetic number, because the mean of its divisors is an integer number (34572973207608).
Almost surely, 2115243244025355 is an apocalyptic number.
115243244025355 is a deficient number, since it is larger than the sum of its proper divisors (23048648805077).
115243244025355 is an equidigital number, since it uses as much as digits as its factorization.
115243244025355 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 23048648805076.
The product of its (nonzero) digits is 2880000, while the sum is 46.
Adding to 115243244025355 its reverse (553520442342511), we get a palindrome (668763686367866).
The spelling of 115243244025355 in words is "one hundred fifteen trillion, two hundred forty-three billion, two hundred forty-four million, twenty-five thousand, three hundred fifty-five".
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