115243403255213 has 2 divisors, whose sum is σ = 115243403255214. Its totient is φ = 115243403255212.

The previous prime is 115243403255143. The next prime is 115243403255231. The reversal of 115243403255213 is 312552304342511.

Together with next prime (115243403255231) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 58394019993604 + 56849383261609 = 7641598^2 + 7539853^2 .

It is an emirp because it is prime and its reverse (312552304342511) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 115243403255213 - 2⁸ = 115243403254957 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (115243403255273) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57621701627606 + 57621701627607.

It is an arithmetic number, because the mean of its divisors is an integer number (57621701627607).

Almost surely, 2^{115243403255213} is an apocalyptic number.

It is an amenable number.

115243403255213 is a deficient number, since it is larger than the sum of its proper divisors (1).

115243403255213 is an equidigital number, since it uses as much as digits as its factorization.

115243403255213 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 432000, while the sum is 41.

Adding to 115243403255213 its reverse (312552304342511), we get a palindrome (427795707597724).

The spelling of 115243403255213 in words is "one hundred fifteen trillion, two hundred forty-three billion, four hundred three million, two hundred fifty-five thousand, two hundred thirteen".